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Extractors must return a reference to an object of type istream. Also, the first parameter must be a reference to an object of type istream. The second parameter is a reference to the variable that will be receiving input. Because it is a reference, the second argument can be modified when information is input. The general form of an extractor is istream &operator>>(istream &stream, class_type &obj ) { // put your extractor code here return stream; }

AS A MATTER OF FACT Don t rush a photo session. Take some time to talk to your subject. Get him or her laughing if you can, even if you want a serious pose. Many people don t like how they appear in photographs. The main reason is that they re tense about being photographed, and this shows in their faces, if not in the outright scowl that appears at the first sight of a camera. If you can get your subject to relax and assure them that no one s going to see a photograph that makes them look bad, you ll both have an easier time of it, and your photo will be a lot better. If possible, take candid photos. There s no rule about whether a portrait should be candid or posed. Both work. But a truly candid pose will capture the person with their guard down. Compare the same person in the two photos in Figure 3-10.

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Many times the integrand has a singularity in the middle of the interval of integration. In these circumstances we divide the integral into two pieces for each of which the integrand is infinite at one endpoint, and evaluate each piece separately.

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2 at c = 1 and 1 at c = 0 1 at c = 1 and 4 at c = 2 0 at c = 0 and 3 at c = 5 3 at c = 3 and 2 at c = 1 1 at c = 0 and 2 at c = 2 x has limits The function f (x) = 2 x 1 (a) 3 at c = 1 and 2 at c = 1 (b) at c = 1 and 0 at c = 1 (c) 0 at c = 0 and nonexistent at c = 1 (d) 2 at c = 2 and 2 at c = 2 (e) at c = 1 and + at c = 1 x3 The function f (x) = x (a) x = 2 and x = 3 if x < 2 is continuous at if x 2

point around which your objects are skewed, as shown in Figure 8-13, which should give you a creative idea for one of the many uses for skewing a duplicate. The skewed copy more or less looks like a cast shadow of the original symbol, doesn t it

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. For nite , the case here, zp(0) = zp(0) = 0, so that the general solution to Eq. (12.3) is y -zw t z( 0) + z( 0)zw n 2 12 2 12 z = z p + 12 sin[(1 - z ) w n t ] + z( 0) cos[(1 - z ) w n t ] e n (12.6) (1 - z 2 ) w n . where the initial conditions z(0) and z(0) are subsumed in zc. Accordingly, for a system initially at rest, the zp solution becomes the complete solution. However, the dif culty with this solution is that is periodic and integration would have to be performed y over many cycles depending on the amount of damping present. Solutions would be analyzed rst to determine the input transient peak response, which is important in cam-follower system performance. Incidentally, the steady-state response would be reached when z( nt ) = ( n + 1)T and z( nt ) = z( n + 1)T .

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